Village Census Code Directory of Arunachal Pradesh, India
According to the 2011 Census of India, the Census village code mapped to the Sibe village in Sibe Taluka is 263708. This village is located in the Sibe Taluka of West Siang district in Arunachal Pradesh state of India.
Name | Mapped Census Code |
---|---|
Sibe Village Code | 263708 |
Sibe Taluka Code | 01639 |
West Siang District Code | 250 |
Arunachal Pradesh State Code | 12 |
The total geographical area of Sibe village is 1500 hectares.
Type (Unit) | Area |
---|---|
Hectare | 1500 ha |
Acre | 3706.5 acre |
Foot | 161458500 ft2 |
Kilometre | 15.0 km2 |
Metre | 15000000 m2 |
Mile | 5.79 mi2 |
Yard | 17940000 yd2 |
The total population of Sibe village is 244 peoples, in which 136 are male and 108 are female. This village sex ratio is 126.
Type | Population |
---|---|
Male | 136 |
Female | 108 |
Sex Ratio | 126 |
1500 ha
46 Houses
Total: 244
Male: 136 Female: 108
126